gusser67:
say for instance I have a shot 160 yards and the wind direction is pointing at 1:30 direction with 10 mph wind what would be easiest way to calculate how many yards to subtract from 160yard shot with full backspin I would think their is a basic way off figuring this shot and many others.
It depends on so many factors, as well as what piztaker said, the built-in deviations in the game.
BUT!
I have my own way of calculating distances that seems to work generally well with my clubs and balls, so be prepared to make adjustments for your own setup. Anyways, here it is in your example.
Distance: 160 yards
Wind: 10mph at 1:30 (or Northeast relative to aiming direction)
Applied backspin: Full
In my own experience, applying full backspin takes off ~3-5% of total distance. I have a 165-yard 7 iron in the R11 Iron Set, so applying full backspin would make it go ~158.4 yards (165*.96).
Additionally, when the wind is under 14 miles per hour. I like to add or subtract half of the wind if it is absolute headwind or absolute tailwind. For example, if I had 10mph headwind, I would add 5 yards. If I had 10mph tailwind, I would subtract 5 yards. However, adjustments must be made when the wind is moving sideways.
If we look at 1:30, that is halfway between absolute headwind and absolute sidewind (midnight and 3:00). So, I can assume that the distance adjustment should be half of what it is if it were to be 10mph tailwind. Thus, I would assume the wind to be 5mph tailwind, and 5mph right sidewind. In adjusting for distance, I would use my same equation from earlier. Take the 5mph and divide by 2: 5/2=2.5. Subtract 2.5 yards from your total distance.
Distance: 160 yards - ~2.5 yards for wind adjustment = ~157.5 yards.
Club: 165 yards * .96 for full backspin = ~158.4 yards.
Thus, hitting my 7 iron (165 yards) with full backspin into that wind SHOULD result in my ball going .9 yards past the hole, or around 2.5 feet.
What I just wrote assumes that you are using lower level balls. Higher level balls will add distance on to your shots, so I probably would have hit the shot around 98% or so, not 165 full.
However, do realize that there are an additional hundreds of factors that could influence the ball's flight, travel, trajectory, etc. No one equation will ever work well 100% of the time, but I do hope this is a good starting point and it gets you as far as it has gotten me. :)