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The best thing I did to better my score

Thu, Nov 7 2013 12:50 AM (75 replies)
  • titus1919
    130 Posts
    Thu, Dec 22 2011 11:50 AM

    I quit thinking of the game as golf.  I treat this game as a giant math game. For example A 23 ft putt on verry fast greens with 3 inch up hill lie

    (23+3)/1.2/6= 3.6 avitar movements on the 30 ft scale for the Rosa putter

    on an approch shot. 155 yards 5 mph wind in the face with an elevated green of 12 feet.

    [[155/[100-(5*.4)]]]+(12/3)=162 yards to the pin then ofcourse add or subtract for back or top spin

     

    So for the approch shot it should be [155+(13/3)] / [.100-(5 x .004)]= 162.2 yards to the pin

    I have gotten quite good at theese calculations so I can do them on a 30 second game. when I started doing all of this on 12/17 I have gone from shooting 1or 2 over par to shootin 33-32 on nine.

     edited to fix error

  • genorb
    1,255 Posts
    Thu, Dec 22 2011 12:09 PM

    You got it :) . But of course there are still things for which you need feelings. For example when you move the aim to counter the wind on an approach shot and to counter the break on the green.

    A small remark which could help you (or not :) ). I didn't follow your math (I think there is a misprint by the way) but I see that you are adding elevation after computing the wind effect. I think you should add it before. Indeed, if you have some elevation and no wind, adding elevation gives you a new effective distance to reach. But now if you have some wind in addition, this wind affect this new effective distance (initial distance + elevation). You could give it a try. With high elevation and/or high wind adding elevation before or after computing the wind effect makes some difference. For low elevation and/or low wind, it does doesn't make a big difference.

    Regards

  • titus1919
    130 Posts
    Thu, Dec 22 2011 12:22 PM

    So for the approch shot it should be [155+(13/3)] / [.100-(5 x .004)]= 162.2 yards to the pin

  • Teedaawg
    276 Posts
    Thu, Dec 22 2011 11:18 PM

    ...very interesting, how does that effect the wind though...whether it's added before or after? I usually devide the elevation by 3 and just add 10 yds or so, depending on the amount for the wind unless its a dead head wind, then I add what ever it says...How do you factor the heavy winds or what formula do you use (genorb)?

    Tee

  • renniw52
    5,385 Posts
    Fri, Dec 23 2011 6:39 AM

    Let's not forget the Vortex inhibitor for SA, and the advanced tree enabled protractor for nbr 2 at BPB. Just lol, not serious here.

  • genorb
    1,255 Posts
    Fri, Dec 23 2011 7:22 AM

    Teedaawg:

    How do you factor the heavy winds or what formula do you use (genorb)?

    Well that's not necessarily a good idea to use the formula from another guy (many would not agree with mine, I am sure). The formula give you an idea of the effective distance to the pin. But then you can still play with the amount of spin you set. For example, if the pin is at an effective distance of 168 yds, I can use my 165yds iron with almost no spin, or use my 180yds with full back spin and reduced power. In addition, all irons do not react the same way. My 165yds iron is a bit short for me while my 150yds iron is a bit long for example.

    You should construct the formula yourself (see below). An important point is that the distance to add or subtract due to the wind is always a % of the distance between you and the target (this is not a constant distance to add). Indeed, let's take the following example. You have a given headwind and you set 100yds of power. The ball travels only 90yds due to the wind. Now you have the same headwind and you set 200yds of power. What would be the distance travelled? Not 190yds but 180yds. indeed, when the ball travels the first 100yds it loses 10yds, but the ball will again lose 10 yds during the remaining 100yds.

    I hope I am clear enough...

    That's not complicated to contruct the formula but it takes some time.

    Collecting the data

    Pick up a course like Kiawah or Bethpage (not STA because the fairway are rolling too much) and tee off with your irons with full power (take for example your 195yds iron (I see you are using the R11 irons)) and the spin you like or use the more (once on the fairway, you can still play another shot). Do it until you get perfect headwind. You need also to ding the shot if you play full back spin. So with full power the ball goes normally to 195yds, but that with that headwind (X1 mph) the ball goes to 180yds. So the factor in the case is

    F(X1) = 195/180 =1.08

    (so you know that with that wind you need to multiply the distance by that factor. So to reach 195 yds you need actually to set 195*1.08 = 211 yds of power)

    Now later on you get another perfect headwind (X2 mph). Again with full power the ball goes normally to 195yds, but that with that headwind (X2 mph) the ball goes to 185yds. The factor in this case is

    F(X2)= 195/185 =1.05

    Ideally, you need to get several data for each value of the wind and you do an average.

    Constructing the formula

    Now you know two things

    1. If there is no wind, the factor is 1. This mean that F(0) = 1
    2. the larger the wind the larger the factor F

    So when you have enough data you can search for the simplest formula (a linear relationship between the factor F and the wind velocity X) which fit your data and is in agreement with the two points above. Such a relation reads

    F(X) = 1 + X * A  

    (indeed F(0) = 1 and F increases linearly when X increases if A is a positive quantity)

    The data you have accumulated will help you to determine what should be the value of the constant A.

    Now of course you still need to figure out how to modify your formula when you have 8 o'clock wind for example (wind between cross wind and full headwind)... That's a bit more tricky.

    I hope I was clear enough.

    Good luck.

    Regards

  • bluescouse
    1,185 Posts
    Fri, Dec 23 2011 7:37 AM

    Anyone else completely lost?

    Sean ;-/

  • LeonDelBosque
    1,551 Posts
    Fri, Dec 23 2011 7:51 AM

    bluescouse:

    Anyone else completely lost?

    Sean ;-/

    It's a game, not a math problem. If that's your thing, then more power to you. I may not be very good, but I don't care if this is what it take to be really good at it. It just wouldn't be any fun for me if I have to turn into an accountant every time I tee off. Of course everyone has to do a little basic number problem solving, but complicated equations, formulas, spread sheets and note taking? No thanks.   

     

  • titus1919
    130 Posts
    Fri, Dec 23 2011 8:32 AM

    Teedaawg:

    How do you factor the heavy winds or what formula do you use (genorb)?

    Tee

    to factor a head wind  it is wind speed x .004 then subtract the answer from 100 then it is yards to pin with elevation change divided by the previous answer

    Same thing for tail wind but you multiply your your elevation adjusted yards by the wind x .004 minus 100

  • MickAnderson
    105 Posts
    Fri, Dec 23 2011 8:49 AM

    LeonDelBosque:

    bluescouse:

    Anyone else completely lost?

    Sean ;-/

    It's a game, not a math problem. If that's your thing, then more power to you. I may not be very good, but I don't care if this is what it take to be really good at it. It just wouldn't be any fun for me if I have to turn into an accountant every time I tee off. Of course everyone has to do a little basic number problem solving, but complicated equations, formulas, spread sheets and note taking? No thanks.   

     

     

    this ^

     

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